X^2=16x+3

Solution for X^2=16x+3 equation:

X^2=16X+3

We move all terms to the left:

X^2-(16X+3)=0

We get rid of parentheses

X^2-16X-3=0

a = 1; b = -16; c = -3;
Δ = b2-4ac
Δ = -162-4·1·(-3)
Δ = 268
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{268}=\sqrt{4*67}=\sqrt{4}*\sqrt{67}=2\sqrt{67}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-2\sqrt{67}}{2*1}=\frac{16-2\sqrt{67}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+2\sqrt{67}}{2*1}=\frac{16+2\sqrt{67}}{2}
$